The loudness (L) of sound in decibels is related to intensity (Umeasured watts per square centimeter by the equation L=10log( 1/(10 ^ - 16) Find the loudness of a whisperat 10^ -12 W/cm^ 2

Respuesta :

Answer:

The loudness of the sound is equal to 40 decibels.

Step-by-step explanation:

Given that,

The loudness (L) of sound in decibels is related to intensity by the equation as follows :

[tex]L=10\ log(\dfrac{I}{I_0})[/tex]

Where

I is the intensity of sound

I₀ is the least audible sound

Put [tex]I=10^{-12}\ W/m^2 \ and\ I_0=10^{-16}\ W/m^2[/tex]

So,

[tex]L=10\ log(\dfrac{10^{-12}}{10^{-16}})\\\\L=40\ dB[/tex]

So, the loudness of the sound is equal to 40 decibels.

Answer:

40

Step-by-step explanation:

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