The magnitude of the frictional force (in newtons) on the block if the block is at rest and the surface is horizontal is 3.67N.
When an object is moving on a rough surface, it experiences opposition. This opposing force is called the friction force.
Given is the coefficients of friction between a block of mass 0.5 kg and a surface are μs = 0.75 and μk = 0.45. Assume the only other force acting on the block is that due to gravity.
The friction force is given by
f = coefficient of friction x Normal force
The block is at rest and the surface is horizontal when gravitational acceleration is g = 9.79 m/s²
f =μs N =μs mg
f = 0.75 x 0.5 x 9.79
f = 3.67 N
Thus, the friction force is 3.67 N.
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