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PLEASE HELP I"LL GIVE 20 POINTSSS Mark estimates that the distance from his house to his school is 15.5 mi. The actual distance is 14.5 mi. To the nearest tenth of a percent, what is the percent error in Mark's estimate? Enter your answer in the box.

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To find the answer, divide the difference between the estimated value by the actual value and multiply the product by a hundred. 15.5-14.5=1
1 mi/14.5mi *100=6.90%(rounded to the nearest tenth)
Therefore the percent error in Mark's estimate is6.90%

Answer:

6.90%

Step-by-step explanation:

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