The function f(x)=18000(0.52)^x represents the value in dollars of a vehicle x years after it has been purchased new. What is the average decrease in value per year between years 4 and 8?
Answers:
-$1219.87/year
-$304.97/year
-$0.52/year
-$18000/year

YEAR 4: $1316.09 -- decreased $16683.91
YEAR 5: $684.37 -- decreased $631.72
YEAR 6: $355.87 -- decreased $328.50
YEAR 7: $185.05 -- decreased $170.82
YEAR 8: $96.23 -- decreased $88.82

The averages of the decreases is equal to 304.97, so the second one is the answer.

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breanna0817 breanna0817 · Answer 2 · 2016-11-18T16:13:19+01:00

breanna0817 breanna0817

18-11-2016

-304.97/year

The function f(x)=18000(0.52)^x represents the value in dollars of a vehicle x years after it has been purchased new. What is the average decrease in value per year between years 4 and 8?

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The function f(x)=18000(0.52)^x represents the value in dollars of a vehicle x years after it has been purchased new. What is the average decrease in value per year between years 4 and 8? Answers: -$1219.87/year -$304.97/year -$0.52/year -$18000/year

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The function f(x)=18000(0.52)^x represents the value in dollars of a vehicle x years after it has been purchased new. What is the average decrease in value per year between years 4 and 8?
Answers:
-$1219.87/year
-$304.97/year
-$0.52/year
-$18000/year