Answer:
103.9 g
Explanation:
First we convert 54.0 g of propane (C₃H₈) into moles, using its molar mass:
- 54.0 g ÷ 44 g/mol = 1.23 mol C₃H₈
Then we convert 1.23 moles of C₃H₈ into moles of CO₂, using the stoichiometric coefficients:
- 1.23 mol C₃H₈ * [tex]\frac{3molCO_2}{1molC_3H_8}[/tex] = 3.69 mol CO₂
We convert 3.69 moles of CO₂ into grams, using its molar mass:
- 3.69 mol CO₂ * 44 g/mol = 162.36 g
And apply the given yield:
- 162.36 g * 64.0/100 = 103.9 g
