The basic dc-dc converter of Fig. 6-2a has a source of 100 V and a load resistance of 10 ⦠The duty ratio of the switch is D = 0.6, and the switching frequency is 1 kHz. Determine (a) the average voltage across the load, (b) the rms voltage across the load, and (c) the average power absorbed by the load. (d) What would happen if the switching frequency were increased to 2 kHz?

Respuesta :

Answer:

a. 60V

b. 77.46V

c. 600 W

d. there would be no effect when this is done

Explanation:

a.

to get value of average output

Vo = VsD

Vs = 100V

D = 0.6

Vo = 100 V * 0.6

Vo = 60V

Therefore 60V is the value of average voltage

b.

The rms voltage:

= Vs√D

= 100 x √0.6

= 100 x 0.7746

= 77.46V

the rms voltage is Therefore 77.46V

c.

value of average power:

= (RMS)²/R

R = 10

when we put into formula above,

= (77.46)²/10

= 6000.05/10

= 600.005 W

= 600W

d.

If switching frequency is changes to be 2khz it would actually have no effect on the average voltage, average power or rms voltage.

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