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When cobalt(II) chloride is allowed to react with sodium hydroxide, the resulting
products are cobalt(II) hydroxide and sodium chloride. Determine the mass of
cobalt(II) chloride required to completely react with 114g of sodium hydroxide.

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Answer:

Reaction CoCl2 + 2 NaOH -> Co(OH)2 + 2 NaOH

You need to count number of moles of NaOH

Amount of mole is n = m/M = 114 g / 39.998 g/mol = 28,5 mol (about)

Amount of CoCl2 is half from that

Calculate molar mass of CoCl2 and multiply it by 28,5 mol

Explanation:

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