thezekromninja
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Can you please solve these systems of equations using elimination for x and y?
1. 8x+2y=46
7x+3y=47

2. 4x+6y=62
7x+3y=47

3. 4x+6y=62
2x+6y=76

4. 8x+1y=43
2x+4y=98
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Respuesta :

mhanifa

Answer:

  • (4.4, 5.4), (3.2, 8.3), (-7, 15), (23 4/15, 2 7/15)

Step-by-step explanation:

1.

Multiply the first equation by 3/2:

  • 3/2×8x + 3/2×2y = 3/2×46    
  • 12x + 3y = 69

Subtract the second equation:

  • 12x - 7x = 69 - 47
  • 5x = 22
  • x = 4.4

Find y:

  • 4*4.4 + y = 23
  • y = 23 - 17.6
  • y = 5.4

2.

Double the second equation and subtract the first one:

  • 14x - 4x = 94 - 62
  • 10x = 32
  • x = 3.2

Find y:

  • 4*3.2 + 6y = 62
  • 6y = 62 - 12.8
  • 6y = 49.8
  • y = 8.3

3.

Subtract the second equation from the first one:

  • 4x - 2x = 62 - 76
  • 2x = -14
  • x = -7

Find y:

  • 4(-7) + 6y = 62
  • 6y = 62 + 28
  • 6y = 90
  • y = 15

4.

Multiply the second equation by 4 and subtract the first one:

  • 16y - y = 4(98) - 43
  • 15y = 349
  • y = 349/15
  • y = 23 4/15

Find x:

  • 8x + 23 4/15 = 43
  • 8x = 19 11/15
  • x = 2 7/15

Answer:

1. [tex]x\x=\frac{22}{5}=4.5, y=\frac{27}{5}=5.5[/tex]

2. [tex]x=\frac{16}{5}=3.2,y=\frac{41}{5}=8.3[/tex]

3. x=−7,y=15.

4. [tex]x=\frac{37}{15}=2\frac{7}{15},y=\frac{349}{15}=23\frac{4}{15}[/tex]

Step-by-step explanation:

I hope this helps.

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