Answer:
4
Step-by-step explanation:
0*(1/3125)+1*(4/625)+2*(32/625)+3*(128/625)+4*(256/625)+5*(1024/3125)
The expected value is an extension of the weighted average in probability theory. The expected value for the given binomial distribution is 4.
The expected value is an extension of the weighted average in probability theory. Informally, the anticipated value is the arithmetic mean of a large number of independently chosen random variable outcomes.
Expected value, E(x) = ∑(Px)
where P is the probability and x is the random distribution value.
The expected value for the given binomial distribution is,
Expected value = Random variable × Probability
E(x) = ∑(Px)
= 0(1/3125) + 1(4/625) + 2(32/625) + 3(128/625) + 4(256/625) + 5(1024/3125)
= 0 + (4/625) + (64/625) + (384/625) + (1024/625) + (5120/3125)
= 0 + 0.0064 + 0.1024 + 0.6144 + 1.6384 + 1.6384
= 4
Hence, the expected value for the given binomial distribution is 4.
Learn more about Expected Value here:
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