Respuesta :

Answer:

Step-by-step explanation:

Prime factorize 27 , 45 and 18

[tex]-3\sqrt{27}-2\sqrt{2}-3\sqrt{45}-\sqrt{18}=-3\sqrt{3*3*3}-2\sqrt{2}-3\sqrt{3*3*5}-\sqrt{3*3*2}\\\\=-3*3\sqrt{3}-2\sqrt{2}-3*3\sqrt{5}-3\sqrt{2}\\\\=-9\sqrt{3}-2\sqrt{2}-9\sqrt{5}-3\sqrt{2}\\\\=-9\sqrt{3}-9\sqrt{5}-2\sqrt{2}-3\sqrt{2}\\\\=-9\sqrt{3}-9\sqrt{5} + (-2-3)\sqrt{2}\\\\=-9\sqrt{3}-9\sqrt{5} - 5\sqrt{2}[/tex]

the answer is -9√3−5√2−9√5.
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