MaverickLandowski MaverickLandowski

17-11-2016
Mathematics

contestada

what is the value of the range of the function f(x) = x squared +2 for the domain value 1/4?

a.) y=2
b.) y=2 1/4
c.) y= 2 1/8
d.) y= 2 1/16

Respuesta :

texaschic101 texaschic101

17-11-2016

ur looking for the range...so u r looking for f(x) or y....and x = 1/4

f(x) = 1/4^2 + 2
f(1/4) = 1/4 * 1/4 + 2
f(1/4) = 1/8 + 2
f(1/4) = 1/8 + 16/8
f(1/4) = 17/8 which equals 2 1/8....so y = 2 1/8

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barbiemafia barbiemafia

17-11-2016

i think the answer is d

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