A system has two components: A and B. The operating times until failure of the two components are independent and exponentially distributed random variables with parameter 2 for component A, and parameter 3 for component B. The system fails at the first component failure.
(a) - Read section 1.5.2 in the textbook.
(b) - What is the mean time to failure for component A and for component B

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MrRoyal MrRoyal · Answer 1 · 2021-03-21T17:33:06+01:00

Answer:

[tex]E(x) = \frac{1}{2}[/tex] -- Component A

[tex]E(x) = \frac{1}{3}[/tex] -- Component B

Step-by-step explanation:

Given

Distribution = Exponential

[tex]\lambda = 2[/tex] --- Component A

[tex]\lambda = 3[/tex] --- Component B

Solving (a): The mean time of A

The mean of an exponential distribution is:

[tex]E(x) = \frac{1}{\lambda}[/tex]

We have:

[tex]\lambda = 2[/tex] --- Component A

[tex]E(x) = \frac{1}{2}[/tex]

Solving (b): The mean time of B

The mean of an exponential distribution is:

[tex]E(x) = \frac{1}{\lambda}[/tex]

We have:

[tex]\lambda = 3[/tex] --- Component B

[tex]E(x) = \frac{1}{3}[/tex]