Respuesta :
Answer: A. Â [tex]LiN_3[/tex] : Lithium (I) nitride.
B. [tex]Ga_2O_3[/tex] : Galium (III) oxide.
C. [tex]RbCl[/tex]: Rubidium (I) chloride.
D. [tex]BaS[/tex] : Barium (II) sulphide.
Explanation:
Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound. Â
A. Here metal Li is having an oxidation state of +1 called as [tex]Li^{+}[/tex] cation and [tex]N^{3-}[/tex] is an anion with oxidation state of -3. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral [tex]LiN_3[/tex]. The name of the compound is Lithium (I) nitride.
B. Here metal Ga is having an oxidation state of +3 called as [tex]Ga^{3+}[/tex] cation and [tex]O^{2-}[/tex] is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral [tex]Ga_2O_3[/tex]. The name of the compound is Galium (III) oxide.
C. Here metal Rb is having an oxidation state of +1 called as [tex]Rb^{+}[/tex] cation and [tex]Cl^{-}[/tex] is an anion with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral [tex]RbCl[/tex]. The name of the compound is Rubidium (I) chloride.
D. Here metal Ba is having an oxidation state of +2 called as [tex]Ba^{+}[/tex] cation and [tex]S^{2-}[/tex] is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral [tex]BaS[/tex]. The name of the compound is Barium (II) sulphide.
