Answer:
The concentration would be 0.76 mol/L.
The most common way to solve this problem is to use the formula
c1V1=c2V2
In your problem,
c1 = 4.2 mol/L; V1 = 45.0 mL
c2 = ?; V2 = 250 mL
c2=c1×V1V2 = 4.2 mol/L × 45.0mL250mL = 0.76 mol/L
This makes sense. You are increasing the volume by a factor of about 6, so the concentration should be about ¹/₆ of the original (¹/₆ × 4.2 = 0.7).
Explanation:
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