Given:
The area of a rectangle = 14 square units.
The side lengths are a and b.
[tex]a=2\dfrac{1}{3}[/tex]
To find:
The value of b.
Solution:
We know that, the area of a rectangle is:
[tex]Area=Length\times Width[/tex]
The area of the given rectangle is:
[tex]14=a\times b[/tex]
[tex]14=2\dfrac{1}{3}\times b[/tex]
[tex]14=\dfrac{2(3)+1}{3}b[/tex]
[tex]14=\dfrac{6+1}{3}b[/tex]
On further simplification, we get
[tex]14=\dfrac{7}{3}b[/tex]
[tex]14\times 3=7b[/tex]
[tex]42=7b[/tex]
Divide both sides by 7.
[tex]\dfrac{42}{7}=b[/tex]
[tex]6=b[/tex]
Therefore, the value of b is 6 units.
