Answer:
[tex]m_{Ag}=135.8gAg[/tex]
[tex]Y=88.4\%[/tex]
Explanation:
Hello there!
In this case, according to the described chemical reaction, it is possible to compute the theoretical mass of silver as mass via the 1:2 mole ratio of copper to silver and their atomic mass in the periodic table, in order to perform the following stoichiometric setup:
[tex]m_{Ag}=40.gCu*\frac{1molCu}{63.55gCu}*\frac{2molAg}{1molCu}*\frac{107.87gAg}{1molAg}\\\\ m_{Ag}=135.8gAg[/tex]
Next, given the actual yield of 120 g, we compute the percent yield via:
[tex]Y=\frac{120g}{135.8g}*100\%\\\\Y=88.4\%[/tex]
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