Answer:
The force of gravitational attraction between the satellite and Earth is [tex]2.587\times 10^{10}[/tex] newtons.
Explanation:
Statement is incorrect. Correct statement is:
A satellite ([tex]m = 4.44\times 10^{9}\,kg[/tex]) travels in orbit around the Earth at a distance of [tex]1.9\times 10^{6}\,m[/tex] above Earth's surface. What is the force of gravitational attraction between the satellite and Earth?
The gravitational force experimented by the satellite ([tex]F[/tex]), in newtons, is calculated by Newton's Law of Gravitation, whose equation is defined by following formula:
[tex]F = \frac{G\cdot m \cdot M}{R^{2}}[/tex] (1)
Where:
[tex]G[/tex] - Gravitational constant, in cubic meters per kilogram-square second.
[tex]m[/tex] - Mass of the satellite, in kilograms.
[tex]M[/tex] - Mass of the Earth, in kilograms.
[tex]R[/tex] - Distance of the satellite with respect to the center of the Earth, measured in meters.
If we know that [tex]G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}[/tex], [tex]m = 4.44\times 10^{9}\,kg[/tex], [tex]M = 5.972\times 10^{24}\,kg[/tex] and [tex]R = 8.271\times 10^{6}\,m[/tex], then the force of gravitational attraction between the satellite and Earth is:
[tex]F = 2.587\times 10^{10}\,N[/tex]
The force of gravitational attraction between the satellite and Earth is [tex]2.587\times 10^{10}[/tex] newtons.
