Answer:
Player A receives $77.34375 of the sakes
Player B receives $22.65625 of the stakes
Step-by-step explanation:
Given that at the time the game was interrupted, we have;
The number of points player A has = 7 points
The number of points player B has = 5 points
The amount the first player to score 10 points wins = $100
The number of points remaining for player A to win the game = 3
The number of points remaining for player B to win the game = 5
Therefore, the number of trials remaining for a winner to emerge = 3 + 5 - 1 = 7 trials
We take the probability that Player A wins a point as success
We find the likelihood of Plater A winning by using binomial theory as follows;
[tex]P(S) = \sum\limits_{j=3}^7 \dbinom{7}{3} \cdot \dfrac{1}{2^7} = \dfrac{35}{128} + \dfrac{35}{128} + \dfrac{21}{128} + \dfrac{7}{128} + \dfrac{1}{128} = \dfrac{99}{128}[/tex]
Therefore, given that the likelihood of Player A winning = 99/128
The stakes should be divided such that Player A gets 99/128 share of the stakes while Player B gets 1 - 99/128 = 29/128 share of the stakes
Therefore, Player A gets (99/128) × $100 = $77.34375
Player B gets (29/128) × $100 = $22.65625
