Answer:
answer below:
Explanation:
1) 4 Al + 3 O2 --> 2Al2O3.
2) Al mol= 28/27 = 1.037mol
O mol= 45/16 = 2.812mol
Al : O
4 : 2
x : 2.812
cross multiply
4 x 2.812/2 = 5.624 mol of Al
Al is limiting reactant
3) 28/5.246 = 5.34product can be formed (not that much sure)
4) 45/ 0.5185 = 86.79
86.79 - 5.34 = 81.45g
5) 50 / 81.45 x 100 = 61.39% ( i guess)
i hope this hleps you
