Answer:
The width of the bigger phone is 2.99 in
Explanation:
Given
[tex]W_1 = 2.6in[/tex]
[tex]L_1 = 5.4in[/tex]
[tex]L_2 = 6.21in[/tex]
See attachment for the measure of cell phones
Required
Determine the width of the bigger version (L2)
To do this, we make use of the following equivalent ratios.
[tex]L_1 : W_1 = L_2 : W_2[/tex]
This gives:
[tex]5.4\ in : 2.6\ in : 6.21\ in : W_2[/tex]
Express as fractions
[tex]\frac{5.4\ in}{2.6\ in} = \frac{6.21\ in}{W_2}[/tex]
[tex]\frac{5.4}{2.6} = \frac{6.21\ in}{W_2}[/tex]
Make W2 the subject
[tex]W_2 = \frac{6.21 * 2.6\ in}{5.4}[/tex]
[tex]W_2 = \frac{16.146\ in}{5.4}[/tex]
[tex]W_2 = 2.99\ in[/tex]
