Answer:
[tex]C=0.596\frac{J}{g\°C}[/tex]
Explanation:
Hello there!
In this case, according to the first law of thermodynamics it is possible to compute the gained heat by the water as shown below:
[tex]Q=\Delta U+W\\\\Q=9185J+346J=9531 J[/tex]
Thus, it is possible to solve for the specific heat of the gas as shown below:
[tex]Q=mC\Delta T\\\\C=\frac{Q}{m\Delta T}=\frac{9531J}{80.0g*(225-25)\°C}\\\\C=0.596\frac{J}{g\°C}[/tex]
Best regards!
