The tire undergoes an angular displacement θ in time t according to
θ = θ₀ + ω₀ t + 1/2 α t ²
where
θ₀ = initial angular displacement
ω₀ = init. ang. velocity
α = ang. acceleration
Here we have θ₀ = 0 and ω₀, so after t = 7.0 s with acceleration α = 2.0 rad/s², the wheel will have been displaced
θ = 1/2 (2.0 rad/s²) (7.0 s)² = 49 rad
making the answer D.
