Answer:
d = 0.0625 m
Step-by-step explanation:
The velocity of an object dropped from a tall building is given by :
[tex]v=\sqrt{64d}[/tex]
Where
d is the distance in feet
We need to find the distance when the velocity is 32 ft/s
Rearranging for d,
[tex]v^2=64d\\\\d=\dfrac{64}{v^2}[/tex]
Put v = 32 ft/s
[tex]d=\dfrac{64}{32^2}\\\\d=0.0625\ m[/tex]
So, the required distance is 0.0625 m.
