Answer:
the height at which the limestone cube must be placed is 0.23 m.
Explanation:
Given;
mass of limestone cube, m₁ = 0.1 kg
initial velocity of the limestone cube, u₁ = 0
mass of steel cube, m₂ = 0.2 kg
initial velocity of the steel cube, u₂ = 0
final velocity of the steel cube, v₂ = 1.5 m/s
Apply the principle of conservation of energy to determine the height of the limestone cube.
Potential energy of the limestone cube at top = Kinetic energy of steel cube at base
m₁gh = ¹/₂m₂v₂²
where;
h is the height at which the limestone cube is placed
[tex]h = \frac{m_2v_2^2}{2m_1g} \\\\h = \frac{0.2\times 1.5 ^2}{2 \times 0.1 \times 9.8} \\\\h =0.23 \ m[/tex]
Therefore, the height at which the limestone cube must be placed is 0.23 m.
