Answer:
31° F and 67° F
Step-by-step explanation:
(a)
When t = 0 then
f(0) = 31 + [tex]\frac{0}{100}[/tex] = 31 + 0 = 31° F
(b)
When t = 10 , then
f(10) = 31 + [tex]\frac{40(10^3)}{10^3+100}[/tex] = 31 + [tex]\frac{40000}{1100}[/tex] = 31 + 36.36... ≈ 67° F
