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Richard Hoskins was the leader of a 4-H club with 27 children. When he divided the club into groups of 5 to play a game, how many groups did he have? How many extra children were there?

Respuesta :

Answer:

5 groups

2 extra children

Step-by-step explanation:

The computation of a number of groups and number of extra children is shown below:

Given that

There is 27 children

And, this group would be divided into group 5

So,

As we know that 25 is easily divided by 5

So there are 5 groups

And, the extra children is

= 27 - 25

= 2 chidren

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