Answer:
28 g CO
Explanation:
First convert grams to moles.
1 mole C = 12.011 g (I'm just going to round to 12 for the sake of this problem)
12 g C • [tex]\frac{1 mol C}{12 g C}[/tex] = 1 mol C
1 mol O = 15.996 g (I'm just going to round to 16)
16 g O • [tex]\frac{1 mol O}{16 g O}[/tex] = 1 mol O
So the unbalanced equation is:
[tex]C + O_{2}[/tex] -> [tex]CO[/tex] (the oxygen has a 2 subscript because it is part of HONClBrIF meaning when not in a compound these elements appear in pairs - called diatomic elements)
The balanced equation is:
[tex]2 C + O_2[/tex] -> [tex]2 CO[/tex]
However, carbon is the limiting reactant in this equation and two moles cannot react because only 12 g (1 mole) are present. Therefore, use the equation
[tex]C + \frac{1}{2} O_2[/tex] -> [tex]CO[/tex].
1 mole of CO is formed, therefore 12 g + 16 g = 28 g CO.
