Step-by-step explanation:
To get the x intercepts you need to set y = 0.
So you will get:
[tex]x^{2}[/tex] - 4x - 12 = 0
which can then be put in the form of:
(x - 6) (x + 2) = 0
The x intercepts are: (6,0) and (-2,0).
For the vertex you would need to convert the equation to vertex form.
which is : y = a[tex](x-h)^{2}[/tex] =k
[tex]x^{2}[/tex] - 4x - 12 = y
turn it in to square form:
([tex]x^{2}[/tex] - 4x + 4) - 12 - 4 = y
[tex](x-2)^{2}[/tex] - 16 = y
so the vertex is = (2, -16)
