Answer:
[tex]Solution,\\Let~a=10in.,~b=24in.~and~c=26in.\\Semiperimeter(s) = \frac{a+b+c}{2}= \frac{10+24+26}{2} = 30in.\\Now,\\Area~of~triangle = \sqrt{s(s-a)(s-b)(s-c)} \\~~~~~~~~~~~~~~~~~~~~~~~~=\sqrt{30(30-10)(30-24)(30-26)} \\~~~~~~~~~~~~~~~~~~~~~~~~=\sqrt{30(20)(6)(4)} = \sqrt{14400}=120sq.inches[/tex]
