Answer:
first number = 8
second number = -5
Step-by-step explanation:
Let
x = first number
y = second number
Two numbers have a difference of 13.
x - y = 13
The sum of twice one number and 3 times the other number is 1
2x + 3y = 1
x - y = 13 (1)
2x + 3y = 1. (2)
From (1)
x = 13 + y
Substitute into (2)
2x + 3y = 1.
2(13 + y) + 3y = 1
26 + 2y + 3y = 1
26 + 5y = 1
5y = 1 - 26
5y = -25
y = -25/5
y = -5
Substitute y = -5 into (1)
x - y = 13
x - (-5) = 13
x + 5 = 13
x = 13 - 5
x = 8
