The standard form of the (3x+1)(x+4) is 3x^2+13x+4=0.
We have given that,
(3x+1)(x+4) using the table of products.
We have to determine the standard form.
What is the formula of the standard form?
The quadratic function f(x) = a(x - h)2 + k, a not equal to zero, is said to be in standard form. If a is positive, the graph opens upward, and if a is negative, then it opens downward. The line of symmetry is the vertical line x = h, and the vertex is the point (h,k).
ax^2+bx+C=0
[tex]=3xx+3x\cdot \:4+1\cdot \:x+1\cdot \:4[/tex]
[tex]=3x^2+13x+4[/tex]
Therefore the standard form is 3x^2+13x+4=0.
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