The local ranger station tracked and tagged 2,844 adult female black bears in a national park. A random sample of 9 adult female black bears from those tagged had an average body weight of 203 pounds with standard deviation 25 pounds. Which of the following is a point estimate for the population mean weight of all female black bears that are tagged?

a. 9
b. 25/√9
c. 25
d. 203
e. 2,844

Respuesta :

fichoh

Answer:

203

Step-by-step explanation:

Sample size, n = 9

Mean weight, m = 203

Standard deviation = 25

Point estimate for the population mean weight of all black bears that are tagged `

The point estimate of the population mean ;

ΣX / n

Sum of sample / sample size ;

This is the mean value formula for the sample.

However, since it has been given in the question that, sample mean weight value = 203 ; then the point estimate of the population mean weight = 203

Option d: 203 is a point estimate for the population mean weight of all female black bears that are tagged.

Given that:

  • Total tagged adult female black bears in the national park = 2,844
  • Sample size = 9
  • Sample mean of body weight of female black bears = 203 pounds.

To find:

Point estimate of population mean weight of female black bears that are tagged.

Calculations and explanations:

Point estimation of population mean is calculated by calculating the mean of the sample drawn from that population. This estimate is considered best guess of population mean.

The sample mean is obtained by:

[tex]\overline{x} = \dfrac{\sum \text{sample observations}}{\text{sample size}}[/tex]

Since it is given that the sample mean is 203, thus we have the point estimate of the population mean as 203 too.

Thus, 203 is a point estimate for the population mean weight of all female black bears that are tagged.

Learn more about point estimate of population mean here:

https://brainly.com/question/20747890

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE