The Students' Conjectures Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Polynomial product B: (x2 + x – 2)(4x2 – 8x)

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Complete Question:

Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Polynomial product B: (x2 + x – 2)(4x2 – 8x) They are trying to determine if the products of the two polynomials are the same. But they disagree about how to solve this problem.

Answer:

[tex]A = B[/tex]

Step-by-step explanation:

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Given

[tex]A: (4x^2 - 4x)(x^2 - 4)[/tex]

[tex]B: (x^2 + x - 2)(4x^2 - 8x)[/tex]

Required

Determine how they can show if the products are the same or not

To do this, we simply factorize each polynomial

For, Polynomial A: We have:

[tex]A: (4x^2 - 4x)(x^2 - 4)[/tex]

Factor out 4x

[tex]A: 4x(x - 1)(x^2 - 4)[/tex]

Apply difference of two squares on x^2 - 4

[tex]A: 4x(x - 1)(x - 2)(x+2)[/tex]

For, Polynomial B: We have:

[tex]B: (x^2 + x - 2)(4x^2 - 8x)[/tex]

Expand x^2 + x - 2

[tex]B:(x^2 + 2x - x - 2)(4x^2- 8x)[/tex]

Factorize:

[tex]B:(x(x + 2) -1(x + 2))(4x^2- 8x)[/tex]

Factor out x + 2

[tex]B:(x -1) (x + 2)(4x^2- 8x)[/tex]

Factor out 4x

[tex]B:(x -1) (x + 2)4x(x- 2)[/tex]

Rearrange

[tex]B: 4x(x - 1)(x - 2)(x+2)[/tex]

The simplified expressions are:

[tex]A: 4x(x - 1)(x - 2)(x+2)[/tex] and  

[tex]B: 4x(x - 1)(x - 2)(x+2)[/tex]

Hence, both polynomials are equal

[tex]A = B[/tex]

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