Answer:
[tex]C_{54}H_{102}O_6[/tex]
Explanation:
Hello!
In this case, since the molar mass of the empirical formula is:
[tex]MM_{empircal}=9*12.01+17*1.01+16.00=141.26g/mol[/tex]
Thus, the ratio of the molecular to the empirical formula is:
[tex]\frac{847g/mol}{141.26g/mol} =6.0[/tex]
Thus, the molecular formula is six times the empirical formula:
[tex]C_{54}H_{102}O_6[/tex]
Best regards!
