Answer:
Acceleration of one cyclist=[tex]2.67m/s^2[/tex]
Yes, the acceleration is higher of another cyclist who accelerates from 0 to 30 m/s in 8 seconds.
Explanation:
We are given that
Initial velocity of one cyclist, u=0 m/s
Final velocity of one cyclist, v=8m/s
Time, t=3 s
Initial velocity of another cyclist, u'=0
Final velocity of another cyclist, v'=30m/s
Time, t'=8 s
We know that
Acceleration, [tex]a=\frac{v-u}{t}[/tex]
Using the formula
[tex]a=\frac{8-0}{3}=\frac{8}{3}=2.67m/s^2[/tex]
Acceleration of one cyclist=[tex]2.67m/s^2[/tex]
Acceleration of another cyclist, a'=[tex]\frac{30-0}{8}m/s^2[/tex]
Acceleration of another cyclist, a'=[tex]3.75m/s^2[/tex]
Yes, the acceleration of another cyclist is higher than the cyclist which accelerates from 0m/s to 8m/s.
