Answer:
[tex]\boxed{\tt x=40^{\circ}}[/tex]
Step-by-step explanation:
∠x, ∠BAC, and ∠CAF form a straight line.
*Sum of angles that are formed on a straight line is equal to 180°.*
[tex]\tt \angle x+\angle BAC+\angle CAF=180^{\circ}[/tex]
[tex]\tt x+\angle BAC+\angle CAF=180^{\circ}[/tex]
[tex]\tt x+80^{\circ}+\angle 60^{\circ}=180^{\circ}[/tex]
Add, 80°+60°=140°
[tex]\tt x+140^{\circ}=180^{\circ}[/tex]
Subtract 140 from both sides:
[tex]\tt x+140^{\circ}-140^{\circ}=180^{\circ}-140^{\circ}[/tex]
[tex]\tt x=40^{\circ}[/tex]
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