Answer:
Given :-
the length of a room is 2 m longer than its breadth .if the area of its floor is 63 sq.m.calculate the length and the breadth of the room
To Find :-
Length and breadth
Answer :-
Let the length and breadth be l + 2 and l
Now,
[tex] \large \sf \: Area = l + 2 \times l [/tex]
[tex] \large \sf \: 63 = l + 2 \times \: l[/tex]
[tex] \large \sf \: 63 = 2l + {l}^{2} [/tex]
[tex] \large \sf \: {l}^{2} + 2l - 63 = 0[/tex]
[tex] \large \sf \: {l}^{2} (9l - 7l) - 63 = 0[/tex]
[tex] \large \sf \: l(l + 9) - 7(l + 9)[/tex]
Either
[tex] \large \sf \: l = - 9[/tex]
or,
[tex] \large \sf \: l = 7[/tex]
Length can't be negative,
So,
L = 9
B = 7
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