Choose the solution to this inequality.
72≥b+95

Answer:
B. [tex]b \leq 1\frac{7}{10}[/tex]
Step-by-step explanation:
Isolate b in order to solve the inequality. Subtract [tex]\frac{9}{5}[/tex] on both sides of the inequality, then simplify. (You will need to convert the fractions in order to subtract and simplify further.)
[tex]\frac{7}{2} \geq b + \frac{9}{5} \\\frac{7}{2} -\frac{9}{5} \geq b + \frac{9}{5} -\frac{9}{5} \\\frac{35}{10} -\frac{18}{10}\geq b\\\frac{17}{10} \geq b\\1\frac{7}{10} \geq b[/tex]
Thus, [tex]b \leq 1\frac{7}{10}[/tex].