The value of "p" will be "0.002".
According to the question,
By subtracting "0.25p" from both sides, we get
→ [tex]100+0.05p-0.25p=0.25p-0.25p[/tex]
[tex]100-0.2p=0[/tex]
[tex]100=0.2p[/tex]
[tex]p = \frac{0.2}{100}[/tex]
[tex]= 0.002[/tex]
Thus the above approach is right.
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