Two times one number added to three times a second number is 21.
The second number is ten less than five times the first number.

Write a system of equations to model this situation and solve.

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Answer:

Step-by-step explanation:

"Two times one number added to three times a second number is 21.

2x + 3y = 21

"The second number is ten less than five times the first number"

y = 5x-10

Substitution

2x+3(5x-10) = 21

2x + 15x - 30 = 21

17x = 51

x = 3

y = 5x-10 = 5

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