Use the graph and table to write the equation that describes the line graphed.

A 2-column table with 5 rows. Column 1 is labeled x with entries negative 2, negative 1, 0, 1, 2. Column 2 is labeled y with entries 1, 2, 3, 4, 5.

The equation of the line
Please help me :(

Use the graph and table to write the equation that describes the line graphedA 2column table with 5 rows Column 1 is labeled x with entries negative 2 negative class=

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Answer:

I believe it is x−y+3=0.

Step-by-step explanation:

y= mx + b

The equation of a line is written as [tex]\frac{y_{2-}{y_{1} } }{x_{2-}{x_{1} } }[/tex], so if you plug in the numbers from the first two rows on the grid you get, [tex]\frac{2-1}{-1--2}[/tex] = [tex]\frac{1}{1}[/tex] = 1

The y- intercept is [tex]b= y_{1}[/tex]-m·[tex]x_{1}[/tex], plug in the number and its, b=1-(1)·(-2)=3

Finally, the equation of the line can be written in the form y=mx+b.

y=x+3.

The equation of the line in the slope-intercept form is y=x+3.

The equation of the line in the point-slope form is y−1=1(x+2).

The general equation of the line is x−y+3=0.

Answer:

It’s D y=X+3

Step-by-step explanation:

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