Answer:
Explanation:
Given that:
[tex]p = 35 + \dfrac{3000}{D}- \dfrac{4800}{D^2}[/tex]
The total revenue = p × D
∴
multiplying both sides by D; we have:
[tex]p\times D = 35 \times D + \dfrac{3000}{D} \times D- \dfrac{4800}{D^2}\times D[/tex]
[tex]= 35 D +3000}{D} - \dfrac{4800}{D}[/tex]
The total cost = (Per unit Variable cost × D) + Advertising cost
The total cost = 38D + 8000
The selling price = 80
From D units, the total revenue = 80D
∴
The break-even will take place when total revenue equals total cost.
So;
8000 + 38D = 80D
8000 = 80 D - 38D
8000 =42D
D = 8000/42
D = 190.48
(b)
Suppose the new sales price
Then;
8000 + 38D = 88D
8000 = 88D - 38D
8000 = 50D
D = 160
Hence, the break-even decreases by:
[tex]\Big(\dfrac{190.48-160}{190.48}\times 100\Big) = 16\%[/tex]
However; suppose the variable cost = 30.4
Then;
8000 + 30.4D = 80D
8000 = 80D - 30.4D
8000 = 49.6D
D = 8000/49.6
D = 161.29
Therefore;
This implies that the break-even decreased by:
[tex]\Big(\dfrac{190.48-161.29}{190.48}\times 100\Big) = 15.32\%[/tex]
Hence, the break-even is more likely to change by 10% in its selling price.