Help me solve this please!!

Answer:
B
Step-by-step explanation:
Using the sine/ cosine ratios in the right triangle and the exact values
sin60° = [tex]\frac{\sqrt{3} }{2}[/tex] , cos60° = [tex]\frac{1}{2}[/tex]
sin60° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{a}{18}[/tex] ( multiply both sides by 18 )
18 × sin60° = a , then
a = 18 × [tex]\frac{\sqrt{3} }{2}[/tex] = 9[tex]\sqrt{3}[/tex]
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cos60° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{b}{18}[/tex] ( multiply both sides by 18 )
18 × cos60° = b , then
b = 18 × [tex]\frac{1}{2}[/tex] = 9