!!!!(Help me please)!!!!

A: We know that the lower quartile is 144, and the upper quartile is 129.5 is you add them all up it is going to equal 273.3. So we know that A can now be crossed out.

B: We know that the lower quartile is 146, and that means the upper quartile is 136.5. So adding all of these numbers up we ill get 282.5 So now B can be crossed out

C: The lower quartile is 114 and the upper quartile is 129.5 and when we add those two numbers up we are going to get 243.5. So we are going to keep this number

D: For the last one we know the lower quartile is 214 and upper is 129.5, and when we add this we get 343.5. So we can cross this out and the only one we have left is going to be C

Hope this help's

abbybemak abbybemak · Answer 2 · 2021-02-18T14:25:21+01:00

Answer:

C lower quartile: 146 upper quartile: 129.5

Step-by-step explanation:

101, 111, 117, 121, 122, 126, 133, 149 Order numbers from least to greatest and find the median.

Median=121.5 The middle is between 121 and 122, so the median is 121.5

111+117 /2 =114 Find the lower quartile by finding the median of the numbers below the overall median. The median of the lower set of data is between 111 and 117, so the lower quartile is 114

126+133 /2 =129.5 Find the upper quartile by finding the median of the numbers above the overall median. The median of the upper set of data is between 126 and 133, so the upper quartile is 129.5