what is the velocity of a 500kg elevator that had 4000 j of energy?

Answer:
4 m/s
Explanation:
wecan do with this formula. igusss cause here we have energy and massa so
lets start
we know KE =1/2 ×m×v^2
kE=4000j
mass = 500 kg
velocity= ?
now ,using formula
KE = 1/2×m× v^2
4000=1/2×500×v^2
4000= 250 × v^2
4000/250= v^2
16= v^2 (power of v becomes square root of 16 while ti goes to akothet side)
v=4 m/s.