Answer:
A. [tex]x_{1} = -44.427^{\circ}\pm n\cdot 360^{\circ}[/tex]
B. [tex]x_{2} = -135.573^{\circ}\pm n\cdot 360^{\circ}[/tex]
Step-by-step explanation:
The negative value of the sine function indicates that [tex]x[/tex] is located at third and fourth quadrants. Besides, this function has a period of 360º. There are two families of solutions:
[tex]x_{1} = \sin^{-1} (-0.7)[/tex]
[tex]x_{1} = -44.427^{\circ}\pm n\cdot 360^{\circ}[/tex]
[tex]x_{2} = \sin^{-1} (-0.7)[/tex]
[tex]x_{2} = -135.573^{\circ}\pm n\cdot 360^{\circ}[/tex]
Hence, right answers are A and B.
