Hi1315
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(a) At the moment, Paul is six times as old as his daughter Jane.
(i) If Jane's present age is x years, write down, in terms of x, the age Paul
will be in 12 years' time.
(ii) In 12 years' time, Paul will be three times as old as Jane. Write down
an equation for x and hence find Jane's present age.

Please help me
will give the brainliest!
Please answer correctly
Need explanation​

Respuesta :

Part (i)

Answer:  6x+12

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Explanation:

Jane's present age is x years old. We replace x with any positive whole number. Currently, Paul is 6 times as old as her, so Paul's current age is 6x years old. In 12 years time, his future age will be 6x+12 years old.

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Part (ii)

Answers:

  • The equation is 6x+12 = 3(x+12)
  • The equation solves to x = 8 which means Jane's present age is 8 years old.  

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Explanation:

If Jane is x years old now, then she will be x+12 years old twelve years into the future. By this point, Paul is 3 times as old as she is, meaning

(Paul's future age) = 3*(Jane's future age)

6x+12 = 3*(x+12)

6x+12 = 3x+36

6x-3x = 36-12

3x = 24

x = 24/3

x = 8

Jane is currently 8 years old. This makes Paul to be 6x = 6*8 = 48 years old currently.

Twelve years from now, Jane and Paull will be 8+12 = 20 years old and 48+12 = 60 years old respectively. We can see that Paul will be three times older than she is since 20*3 = 60. This helps confirm we have the correct answers.

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