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Answer:
[tex]\text{c. }f(n)=3f(n-1);f(1)=2[/tex]
Step-by-step explanation:
The first term is 2, so part of the recursive definition is ...
f(1) = 2
The common ratio is 6/2 = 3, so each term is 3 times the previous one. That part of the recursive definition is ...
f(n) = 3·f(n -1)
These two parts of the definition match choice C.