Answer:
-8, -2 and 4
Step-by-step explanation:
Let the terms of the AP be a-d, a and a+d
If the sum is 6, then;
a-d+a+a+d = -6
3a = -6
a = -6/3
a = -2
Hence the first term is 6
If the product is 64
(a-d)(a)(a+d) = 64
-2(a²-d²) = 64
-2(4-d²) = 64
4-d² = -64/2
4-d² = -32
-d² = -32-4
-d² = -36
d² = 36
d = 6 or -6
The first term is a-d = -2-6 = -8
second term is a = -2
third term is a+d = -2+6 = 4
Hence the required AP is -8, -2 and 4
