Answer:
[tex]n =1.905mol[/tex]
Explanation:
Hello!
In this case, by considering helium gas as an ideal one, we can use the following equation:
[tex]PV=nRT[/tex]
Whereas P should go in atmospheres and T in Kelvins; thus we proceed as follows:
[tex]n=\frac{PV}{RT}=\frac{132kPa*\frac{1atm}{101.325kPa}*36L}{0.08206\frac{atm*L}{mol*K}(27+273)K} =1.905mol[/tex]
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